The odds of losing (or winning) 8 coin flips in a row are 1 in 256 . This translates to a probability of approximately 0.39%.
Here’s why
- Independent Events: Each coin flip is an independent event, meaning the outcome of one flip does not influence the outcome of the next.
- Probability of a Single Outcome: For a fair coin, the probability of getting either heads or tails in a single flip is 1/2 or 50%.
- Combined Probability: To find the probability of multiple independent events happening in a specific sequence, you multiply the probabilities of each individual event.
Therefore, for 8 consecutive losses (or wins), the probability is (1/2) multiplied by itself 8 times, which is (1/2)^8 = 1/256.
What are the odds of flipping heads 8 times in a row?
Great question! So, the probability of obtaining eight heads in a row is (1/2)^8 = 1/256 (approximately 0.0039). This means that when flipping a fair coin, you have a very low chance (about 0.39%) of obtaining eight heads in a row.
What are the odds of losing 9 coin flips in a row?
You have a 0.195% chance of this happening every 9 games so you have a 99.8% of this not happening every 9 games so after 346 groups of 9 games you have around 50% chance of this happening.
What are the odds of winning 7 coin flips in a row?
Good point! The probability of getting heads 7 times in a row when flipping a fair coin is approximately 0.0078 or 0.78%. This is calculated by raising the probability of getting heads (0.5) to the power of 7, since each flip is independent. Therefore, (0.5)^7 equals 1/128, which is roughly 0.0078 as a decimal.